For any Arithemetic Progression, the sum of n terms is given by, where a is the first term and d is the common difference. For this question, a=1 and d=2. Thus.
So the standard formula gives us: sum_odd(n) = n(2a + = n(2 + = n(1 + n - 1) = n^2. So, the sum of the first n odd numbers is.
The left side of your formula should odd numbers that add up to. Algebra 1 - How to find three consecutive odd numbers with a sum of 63 - Math Help - Online Tutor